is a product of two complex numbers, namely
and
, which we wish to determine.
is itself derived
from the measured quantity
. Numerically speaking, each
term in the summation of the numerator of Equation D.8
will involve
(via
) and the multiplication of
with
would give
an effective weight of
. Since the denominator is the sum of this
effective weight, the right-hand side of Equation D.8 can
be interpreted as the weighted average of
over all correlations
with antenna
.
In the very first iteration, when , the normalization would
be incorrect since the numeric value of
, as it appears inside
would be different from that used in the denominator of
Equation D.8. However, as the estimates of
s improve
with iterations, the equation would progressively approach a true
weighted average equation. The speed of convergence will depend upon
the value of
and the convergence would be defined by the
constraint in Equation D.10. In the ideal case
when the true value of all
s is known, right hand side of
Equation D.8 also reduces of
.
Estimating for an antenna, by averaging over the measurements
from all baselines in which it participates (for a unresolved source)
makes sense since for an N element array,
would be present in
N-1 measurements (all the
) and
the best estimate of
would be the weighted average of all these
measurements. Proper weight for
, buried in each of the products
, can be found heuristically as follows.
, estimated
from the measurements of a given baseline, must obviously be weighted
by the signal-to-noise ratio on that baseline. This is
in
the above equations. It must also be weighted by the amplitude gain
of the other antenna making the baseline, namely
, to account for
variation in antenna sensitivities and
. The total weight for
would then be
, the sum of which
appears in the denominator of Equation D.8. Knowing that
ideally
, each of the
must be multiplied by
(to apply
the the above mentioned weights to
), before being summed for all
values of
and normalized by the sum of weights to form the
weighted average of
. One thus arrives at
Equation D.8 using these heuristic arguments.