Eq. 8 offers itself for some intuitive understanding in the following way.
is a product of two complex numbers, namely
and
, which we wish to determine.
is itself derived from
the measured quantity
. Numerically speaking, each term
in the summation of the numerator of Eq. 8 will involve
(via
) and the multiplication of
with
would give
an effective weight of
.
Since the denominator is the sum of this effective weight, the
right-hand side of Eq. 8 can be interpreted as the weighted
average of
over all correlations with antenna
.
In the very first iteration, when
, the normalization would
be incorrect since the numeric value of
as it appears inside
would be different from that used in the denominator of
Eq. 8. However, as the estimates of
s improve with
iterations, the equation would progressively approach a true weighted
average equation. The speed of convergence will depend upon the value
of
and the convergence would be defined by the constraint in
Eq. 10. In the ideal case when the true value of all
s is known, right hand side of Eq. 8 also reduces of
.
Estimating
for an antenna, by averaging over the measurements
from all baselines in which it participates (for a unresolved source)
makes sense since for an N element array,
would be present in
N-1 measurements (all the
) and the best
estimate of
would be the weighted average of all these
measurements. Proper weight for
, buried in each of the products
, can be found heuristically as follows.
, estimated
from the measurements of a given baseline, must obviously be weighted
by the signal-to-noise ratio on that baseline. This is
in
the above equations. It must also be weighted by the amplitude gain
of the other antenna making the baseline, namely
, to account for
variation in antenna sensitivities and
. The total weight
for
would then be
, the sum of which
appears in the denominator of Eq. 8. Knowing that ideally
, each of the
must be
multiplied by
(to apply the the above mentioned weights
to
), before being summed for all values of
and normalized by
the sum of weights to form the weighted average of
. One thus
arrives at Eq. 8 using these heuristic arguments.